MBIN: LimitTakHingga

Home Posts filed under LimitTakHingga

Tampilkan postingan dengan label LimitTakHingga. Tampilkan semua postingan

$limlimits_{x oinfty}({sqrt{2x^2+5x+8}}-sqrt{2x^2+2x-1})=dots$ Kelas11 Limit LimitTakHingga

$lim_{x \to \infty} (\sqrt{2 x^{2} + 5 x + 8} - \sqrt{2 x^{2} + 2 x - 1}) = \dots$

✔ mbindog_02 Juni 26, 2022

lim_{x \to \infty} (\sqrt{2 x^{2} + 5 x + 8} - \sqrt{2 x^{2} + 2 x - 1}) = \dots

......

$limlimits_{x oinfty}{(3x-2)}-sqrt{9x^2-2x+5})=dots$ Kelas11 Limit LimitTakHingga

✔ mbindog_02 Juni 26, 2022

lim_{x \to \infty} (3 x - 2) - \sqrt{9 x^{2} - 2 x + 5}) = \dots

......

$limlimits_{x oinfty}{(2x-1)}-sqrt{4x^2-6x-5})=dots$ Kelas11 Limit LimitTakHingga

✔ mbindog_02 Juni 26, 2022

lim_{x \to \infty} (2 x - 1) - \sqrt{4 x^{2} - 6 x - 5}) = \dots

......

$limlimits_{x oinfty}(sqrt{(x+5)(4x+7)}-sqrt{(x+3)(4x+7)})=dots$ Kelas11 Limit LimitTakHingga

✔ mbindog_02 Juni 26, 2022

lim_{x \to \infty} (\sqrt{(x + 5) (4 x + 7)} - \sqrt{(x + 3) (4 x + 7)}) = \dots

......

$limlimits_{x oinfty}(sqrt{x(4x+5)}-sqrt{4x^2-3})=dots$ Kelas11 Limit LimitTakHingga

✔ mbindog_02 Juni 24, 2022

lim_{x \to \infty} (\sqrt{x (4 x + 5)} - \sqrt{4 x^{2} - 3}) = \dots

......

$limlimits_{x oinfty}(sqrt{x^2+2x+1}-sqrt{x^2-3x+4})=dots$ Kelas11 Limit LimitTakHingga

✔ mbindog_02 Juni 24, 2022

(adsbygoogle = window.adsbygoogle......

$limlimits_{x oinfty}(sqrt{4x^2+4x-3}-(2x-5))=dots$ Kelas11 Limit LimitTakHingga

✔ mbindog_02 Juni 24, 2022

lim_{x \to \infty} (\sqrt{4 x^{2} + 4 x - 3} - (2 x - 5)) = \dots

......