Diketahui fungsi f(x)=x+1, g(x)=x2−5x−3, dan h(x)=3x−1. Tentukan:
a. (f∘g∘h)(x)
b. (g∘h∘f)(x)
Jawab
f(x)=x+1
(f∘g)(x)=(x2−5x−3)+1
(f∘g)(x)=x2−5x−2
(f∘g∘h)(x)=(3x−1)2−5(3x−1)−2
(f∘g∘h)(x)=9x2−6x+1−15x+5−2
(f∘g∘h)(x)=9x2−21x+4
g(x)=x2−5x+3
(g∘h)(x)=(3x−1)2−5(3x−1)+3
(g∘h)(x)=9x2−6x+1−15x+5+3
(g∘h)(x)=9x2−21x+9
(g∘h∘f)(x)=9(x+1)2−21(x+1)+9
(g∘h∘f)(x)=9(x2+2x+1)−21x−21+9
(g∘h∘f)(x)=9x2+18x+9−21x−21+9
(g∘h∘f)(x)=9x2−3x−3
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