Jika f(x)=x^2+3x-4, g(x)=x-4, dan h(x)=2x+1

Jika $f (x) = x^{2} + 3 x - 4$ , $g (x) = x - 4$ , dan $h (x) = 2 x + 1$ , komposisi fungsi $(f \circ g \circ h) (x) = \dots$

a. $4 x^{2} - 6 x - 4$

b. $4 x^{2} + 6 x - 4$

c. $x^{2} + 6 x - 7$

d. $x^{2} + 5 x - 3$

e. $x^{2} + 4 x - 8$

Penyelesaian

Diketahui:

$f (x) = x^{2} + 3 x - 4$

$g (x) = x - 4$

$h (x) = 2 x + 1$

Ditanya: $(f \circ g \circ h) (x) = ?$

jawab

$f (x) = x^{2} + 3 x - 4$

$(f \circ g) (x) = (x - 4)^{2} + 3 (x - 4) - 4$

$(f \circ g) (x) = x^{2} - 8 x + 16 + 3 x - 12 - 4$

$(f \circ g) (x) = x^{2} - 5 x$

$(f \circ g \circ h) (x) = (2 x + 1)^{2} - 5 (2 x + 1)$

$(f \circ g \circ h) (x) = 4 x^{2} + 4 x + 1 - 10 x - 5$

$(f \circ g \circ h) (x) = 4 x^{2} - 6 x - 4$

Jawaban : a

Muda Berkarya Intelektual Normatif

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