Jika f(x)=x^2+2x-1 dan g(x)=3x-5

Jika $f (x) = x^{2} + 2 x - 1$ dan $g (x) = 3 x - 5$ , nilai $lim_{x \to 1} (2 f (x) - 5 g (x)) = \dots$

A. $- 14$

B. $- 6$

C. $3$

D. $6$

E. $14$

Penyelesaian

Diketahui:>

$f (x) = x^{2} + 2 x - 1$

$g (x) = 3 x - 5$

Jawab

$lim_{x \to 1} (2 (x^{2} + 2 x - 1) - 5 (3 x - 5))$

$= lim_{x \to 1} (2 x^{2} + 4 x - 2 - 15 x + 25)$

$= lim_{x \to 1} (2 x^{2} - 11 x + 23)$

$= (2 (1)^{2} - 11 (1) + 23) = 14$

Jawaban : E

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