Nilai lim x mendekati ∞ (√(4x^2-8x+3)-(2x-1))

Nilai $\lim \limits_{x\to \infty}(\sqrt{4x^2-8x+3}-(2x-1)) =\dots$

A. -4

B. -1

C. $\frac{1}{4}$

D. $\frac{1}{2}$

E. 2

Penyelesaian

$(2x-1)^2=4x^2-4x+1$

Soal bisa di modiv menjadi

$\lim \limits_{x\to \infty}(\sqrt{4x^2-8x+3}-\sqrt{4x^2-4x+1})$

$a=4$

$b=-8$

$q=-4$

Rumus: $\frac{b-q}{2\sqrt{a}}$

$=\frac{-8-(-4)}{2\sqrt{4}}$

$=\frac{-4}{4}=-1$

Jawaban : B

Muda Berkarya Intelektual Normatif