Nilai lim x mendekati 2 (x^2+4x-12)/(x^2-6x+8)

Nilai $\lim \limits_{x\to 2} \frac{x^2+4x-12}{x^2-6x+8}=\dots$

A. -4

B. -2

C. $\frac{1}{4}$

D. 2

E. 4

Penyelesaian

$\lim \limits_{x\to 2}\frac{x^2+4x-12}{x^2-6x+8} $

$=\lim \limits_{x\to 2}\frac{(x+6)(x-2)}{(x-4)(x-2)}$

$=\lim \limits_{x\to 2}\frac{x+6}{x-4}=\frac{2+6}{2-4}=\frac{8}{-2}=-4$

Jawaban : A

Muda Berkarya Intelektual Normatif