Jika f(x)=x+1, g(x)=3x-2, dan h(x)=x^2-2x+5

 

Jika $f(x)=x+1$, $g(x)=3x-2$, dan $h(x) = x^2-2x+5$, nilai $( g\circ h \circ f )(-1)=...$

a. -7

b. -2

c. 5

d. 9

e. 13

Pembahasan

Diketahui:

$f(x)=x+1$

$g(x)=3x-2$

$h(x) = x^2-2x+5$

Ditanya:

$( g\circ h \circ f )(-1)=...$

jawab

$(g\circ h \circ f)(x) = (g(h(x+1)))$

$(g\circ h \circ f)(x) = (g((x+1)^2-2(x+1)+5))$

$(g\circ h \circ f)(x) = (g(x^2+2x+1-2x-2+5))$

$(g\circ h \circ f)(x) = (g(x^2+4))$

$(g\circ h \circ f)(x) = (3(x^2+4)-2) $

$(g\circ h \circ f)(x) = 3x^2 +12-2$

$(g\circ h \circ f)(x) = 3x^2 +10$

$(g\circ h \circ f)(-1) = 3(-1)^2 +10$

$(g\circ h \circ f)(x) = 3+10$

$(g\circ h \circ f)(x)=13$

Kesimpulan

Jadi, nilai $(g\circ h \circ f)(-1)$ adalah 13

Jawaban:e

Muda Berkarya Intelektual Normatif