Jika f(x)=x^2+4x-5

Jika $f(x)=x^2+4x-5$, nilai$\underset{x\to 3}{lim}7\sqrt{f(x)}=\dots$

A. 7

B. 14

C. 21

D. 28

E. 35

Penyelesaian

$\underset{x\to 3}{lim}7\sqrt{f(x)}=\underset{x\to 3}{lim}7\sqrt{x^2+4x-5}$

$\underset{x\to 3}{lim}7\sqrt{f(x)}=\underset{x\to 3}{lim}7\sqrt{3^2+4(3)-5}$

$\underset{x\to 3}{lim}7\sqrt{f(x)}=7\sqrt{9+12-5}$

$=7\sqrt{16}=7\times 4=28$

Jawaban : D

Muda Berkarya Intelektual Normatif

Muda Berkarya Intelektual Normatif