Hasil lim x→∞ (-2x^{2}-3x+2)\(6x^(2)+x-3)

Hasil $\underset{x\to \mathrm{\infty }}{lim}\frac{-2x^2-3x+2}{6x^2+x-3}=...$

A. $-\frac{1}{6}$

B. $-\frac{1}{3}$

C. $-\frac{1}{2}$

D. $\frac{1}{3}$

E. $\frac{1}{6}$

Pembahasan

$\underset{x\to \mathrm{\infty }}{lim}\frac{-2x^2-3x+2}{6x^2+x-3}$

$=\underset{x\to \mathrm{\infty }}{lim}\frac{\frac{-2x^2}{x^2}-\frac{3x}{x^2}+\frac{2}{x^2}}{\frac{6x^2}{x^2}+\frac{x}{x^2}-\frac{3}{x^2}}$

$=\underset{x\to \mathrm{\infty }}{lim}\frac{-2-0+0}{6+0-0}=\frac{-2}{6}=-\frac{1}{3}$

Kesimpulan

Jadi, nilai dari $\underset{x\to \mathrm{\infty }}{lim}\frac{-2x^2-3x+2}{6x^2+x-3}$ adalah $-\frac{1}{3}$

Jawaban : B

Muda Berkarya Intelektual Normatif

Muda Berkarya Intelektual Normatif