Hasil lim x→∞ (-2x^{2}-3x+2)\(6x^(2)+x-3)

limit

Hasil $\lim \limits_{x \to \infty}{\frac {-2x^{2}-3x+2}{6x^{2}+x-3}}=... $

A. $-\frac{1}{6} $

B. $-\frac{1}{3} $

C. $- \frac {1}{2} $

D. $\frac {1}{3} $

E. $\frac {1}{6} $

Pembahasan

$\lim \limits_{x \to \infty}{\frac {-2x^{2}-3x+2}{6x^{2}+x-3}}$


$=\lim \limits_{x \to \infty}{\frac {\frac{-2x^{2}}{x^{2}}-\frac{3x}{x^{2}}+\frac {2}{x^{2}}} {\frac {6x^{2}}{{x^{2}}}+\frac{x}{x^{2}}-\frac{3}{x^{2}}}}$


$=\lim \limits_{x\to \infty}{\frac {-2-0+0}{6+0-0}}=\frac{-2}{6}=-\frac {1}{3} $


Kesimpulan

Jadi, nilai dari $\lim \limits_{x \to \infty}{\frac {-2x^{2}-3x+2}{6x^{2}+x-3}}$ adalah $-\frac{1}{3} $

Jawaban : B

Muda Berkarya Intelektual Normatif