Nilai $\lim\limits_{x\to 1}(x^4+x^3-3x^2-1)(x^3-2x+3)=\dots$

Nilai

lim_{x \to 1} (x^{4} + x^{3} - 3 x^{2} - 1) (x^{3} - 2 x + 3) = \dots

Nilai $lim_{x \to 1} (x^{4} + x^{3} - 3 x^{2} - 1) (x^{3} - 2 x + 3) = \dots$

A. $- 8$

B. $- 4$

C. $0$

D. $8$

E. $4$

Penyelesaian

cara substitusi

$lim_{x \to - 3} (x^{4} + x^{3} - 3 x^{2} - 1) (x^{3} - 2 x + 3)$

$= (1^{4} + 1^{3} - 3 (1)^{2} - 1) (1^{3} - 2 (1) + 3)$

$= (- 2) (2)$

$= - 4$

Kesimpulan

Jadi nilai $lim_{x \to - 3} (x^{4} + x^{3} - 3 x^{2} - 1) (x^{3} - 2 x + 3) = - 4$

Jawaban: B

        
          Muda Berkarya Intelektual Normatif

            Muda Berkarya Intelektual Normatif

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